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BECE: MATHEMATICS

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Paper 3 – Theory | 2022 BECE Mathematics

BECE: MATHEMATICS 2022 BECE (Junior WAEC) Mathematics Past Questions Paper 3 – Theory | 2022 BECE Mathematics
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2022 JSCE Mathematics Theory Past Question 1

(a) Solve the equation \( \frac{3x\:-\:5}{10} = \frac{8\:+\:5x}{5} \)

Solution:

Cross multiply

5(3x – 5) = 10(8 + 5x)

15x – 25 = 80 + 50x

collect like terms

15x – 50x = 80 + 25

-35x = 105

divide both sides by -35

⇒ \( \frac{-35x}{-35} = \frac{105}{-35} \)

∴ x = -3

(b) 342five

1st Step: convert to base 10

342five = 3 × 5² + 4 × 5¹ + 2 × 50

= 3 × 25 + 4 × 5 + 2 × 1

= 75 + 20 + 2

= 97ten

2nd Step: Convert to binary

97ten = 1100001two

∴ 342five = 97ten = 1100001two

2022 JSCE Mathematics Theory Past Question 2

(a) Calculate the 4th angle of a quadrilateral whose other three angles are 52º, 120º and 125º

Solution:

Sum of the interior angles of a quadrilateral is 360°

∴ 52º + 120º + 125º + x = 360º

297º + x = 360º

x = 360º – 297º

x = 63º

 

(b) The table below shows the scores of students in a test

(i) What is the modal score?

Answer: Score with the highest number = Modal score = 25

(ii) How many students took part in the test?

Answer: 15 students

(iii) Find the median score.

We can calculate the median from the cumulative frequency table shown above.

Total number of students = 15

∴ The median is the 8th student

From the table, the cumulative frequency that holds the 8th student is 10, corresponding to a score 0f 24.

∴ The medianscore = 24

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