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JSS1: MATHEMATICS - 1ST TERM

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  1. Whole Numbers I | Week 1
    3 Topics
    |
    1 Quiz
  2. Whole Numbers II | Week 2
    1 Topic
    |
    1 Quiz
  3. Counting in Base Two | Week 3
    4 Topics
    |
    1 Quiz
  4. Arithmetic Operations | Week 4
    3 Topics
    |
    1 Quiz
  5. Lowest Common Multiple (LCM) | Week 5
    2 Topics
    |
    1 Quiz
  6. Highest Common Factor | Week 6
    1 Topic
    |
    1 Quiz
  7. Fraction | Week 7
    7 Topics
    |
    1 Quiz
  8. Basic Operations with Fractions I | Week 8
    3 Topics
    |
    1 Quiz
  9. Basic Operations with Fractions II | Week 9
    1 Topic
    |
    1 Quiz
  10. Directed Numbers | Week 10
    3 Topics
    |
    1 Quiz
  11. Estimation and Approximation I | Week 11
    3 Topics
    |
    1 Quiz
  12. Estimation and Approximation II | Week 12
    6 Topics
    |
    1 Quiz



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There are two different method of solving binary multiplication. 

1. Using long multiplication method.
2. Using conversion method.

Example:

Calculate the product of 1011two and 101two 

Solution 

1st Method

Using long multiplication  

Note:

0 x 0 = 0 
0 x 1 = 1 
1 x 0 = 0 
1 x 1 = 1

Screenshot 2022 08 21 at 13.10.28

⇒ 1011two x 101two = 110111two

2nd Method

Solving the same question using conversion

1011two x 101two 

Convert the numbers to base 10 and multiply. Then convert the result to base 2 

1011two = 1 x 23 + 0 x 22 + 1 x 21 + 1 x 20 

= 1 x 8 + 0 x 4 + 1 x 2 + 1 x 1 

= 8 + 0 + 2 + 1 

= 11ten 

Also, 

101two = 1 x 22 + 0 x 21 + 1 x 20 

1 x 4 + 0 x 2 + 1 x 1 

4 + 0 + 1 

= 4 + 1 = 5ten 

Therefore, 11ten x 5ten = 55ten. 

Now we can convert 55ten to base two

kna e1605908599413

 55ten = 1100111two
⇒ 1011two x 101two = 110111two 

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