JSS1: MATHEMATICS  1ST TERM

Whole Numbers I  Week 13 Topics1 Quiz

Whole Numbers II  Week 21 Topic1 Quiz

Counting in Base Two  Week 34 Topics1 Quiz

Arithmetic Operations  Week 43 Topics1 Quiz

Lowest Common Multiple (LCM)  Week 52 Topics1 Quiz

Highest Common Factor  Week 61 Topic1 Quiz

Fraction  Week 77 Topics1 Quiz

Basic Operations with Fractions I  Week 83 Topics1 Quiz

Basic Operations with Fractions II  Week 91 Topic1 Quiz

Directed Numbers  Week 103 Topics1 Quiz

Estimation and Approximation I  Week 113 Topics1 Quiz

Estimation and Approximation II  Week 126 Topics1 Quiz
Solving Word Problems Involving Fractions
Topic Content:
 Solving Word Problems Involving Fractions
Problems involving fractions often appear in reallife situations.
Worked Example 9.1.1:
The length of a field is 30m and the breadth is 20m. Calculate \(\frac{1}{10}\)of the area of the field.
Solution
Area of the field = length × breadth
= 30m × 20m
= 600m^{2}
Hence, \(\frac {1}{10} \scriptsize \: of \: 600m^2\)
=\(\frac {1}{10} \scriptsize \: \times \: 600m^2\)
= 60m^{2}
Therefore, \(\frac{1}{10}\) of the area of the field is 60m^{2}.
Worked Example 9.1.2:
A loaf of bread was divided into 24 equal sides. If 8 slices were given to Segun, what fraction is left?
Solution
This question can be solved using two different methods.
Method 1
Let the whole loaf of bread be 1.
Since 8 out of 24 was given out, so this represents \( \frac{8}{24} \) of the total.
The amount left = \( \scriptsize 1\: \: \normalsize \frac{8}{24} \)
Note: \( \frac{24}{24} \scriptsize = 1 \)
\( \scriptsize 1\: – \: \normalsize \frac {8}{24}\\ = \frac{24}{24}\: – \: \frac{8}{24} \\ = \frac{16}{24} \\ = \frac{2}{3}\)The fraction left is \(\frac{2}{3}\)
Method 2
The original loaf has 24 slices. Since 8 slices were given to Segun, the remaining slices = 24 – 8 = 16.
The fraction left = \( \frac{16}{24} \\ = \frac{2}{3}\)
Worked Example 9.1.3:
Mr. Oladele received N2,500 as his salary last month. He spent ^{1}/_{2} of it on food, ^{1}/_{4} on house rent, ^{1}/_{10 }on transport, and the rest on miscellaneous things.
i. Find the amount he spent on each of these items?
ii. What fraction of his salary was spent on miscellaneous things?
Solution
i. Total amount received = ₦2,500
For food = ^{1}/_{2} of ₦2,500
= ^{1}/_{2} × ₦2,500
= ₦1,250
For House rent = ^{1}/_{4} of ₦2,500
= ^{1}/_{4} × N2,500
= ₦625.
For Transport = ^{1}/_{10} of ₦2,500
= ^{1}/_{10} × ₦2,500
= ₦250
Total spent = ₦1250 + ₦625 + ₦250
= ₦ 2,215
Miscellaneous = ₦2500 – ₦2,125
= ₦375
ii. The fraction of the salary spent on miscellaneous is
= \(\frac{375}{2500} \\ = \frac{75}{100} \\ = \frac{15}{100} \\ = \frac{3}{20}\)