JSS1: MATHEMATICS - 1ST TERM
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Whole Numbers I | Week 13 Topics|1 Quiz
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Whole Numbers II | Week 21 Topic|1 Quiz
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Counting in Base Two | Week 34 Topics|1 Quiz
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Arithmetic Operations | Week 43 Topics|1 Quiz
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Lowest Common Multiple (LCM) | Week 52 Topics|1 Quiz
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Highest Common Factor | Week 61 Topic|1 Quiz
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Fraction | Week 77 Topics|1 Quiz
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Basic Operations with Fractions I | Week 83 Topics|1 Quiz
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Basic Operations with Fractions II | Week 91 Topic|1 Quiz
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Directed Numbers | Week 103 Topics|1 Quiz
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Estimation and Approximation I | Week 113 Topics|1 Quiz
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Estimation and Approximation II | Week 126 Topics|1 Quiz
Solving Word Problems Involving Fractions
Topic Content:
- Solving Word Problems Involving Fractions
Problems involving fractions often appear in real-life situations.
Worked Example 9.1.1:
The length of a field is 30m and the breadth is 20m. Calculate \(\frac{1}{10}\)of the area of the field.
Solution
Area of the field = length × breadth
= 30m × 20m
= 600m2
Hence, \(\frac {1}{10} \scriptsize \: of \: 600m^2\)
=\(\frac {1}{10} \scriptsize \: \times \: 600m^2\)
= 60m2
Therefore, \(\frac{1}{10}\) of the area of the field is 60m2.
Worked Example 9.1.2:
A loaf of bread was divided into 24 equal sides. If 8 slices were given to Segun, what fraction is left?
Solution
This question can be solved using two different methods.
Method 1
Let the whole loaf of bread be 1.
Since 8 out of 24 was given out, so this represents \( \frac{8}{24} \) of the total.
The amount left = \( \scriptsize 1\: -\: \normalsize \frac{8}{24} \)
Note: \( \frac{24}{24} \scriptsize = 1 \)
\( \scriptsize 1\: – \: \normalsize \frac {8}{24}\\ = \frac{24}{24}\: – \: \frac{8}{24} \\ = \frac{16}{24} \\ = \frac{2}{3}\)The fraction left is \(\frac{2}{3}\)
Method 2
The original loaf has 24 slices. Since 8 slices were given to Segun, the remaining slices = 24 – 8 = 16.
The fraction left = \( \frac{16}{24} \\ = \frac{2}{3}\)
Worked Example 9.1.3:
Mr. Oladele received N2,500 as his salary last month. He spent 1/2 of it on food, 1/4 on house rent, 1/10 on transport, and the rest on miscellaneous things.
i. Find the amount he spent on each of these items?
ii. What fraction of his salary was spent on miscellaneous things?
Solution
i. Total amount received = ₦2,500
For food = 1/2 of ₦2,500
= 1/2 × ₦2,500
= ₦1,250
For House rent = 1/4 of ₦2,500
= 1/4 × N2,500
= ₦625.
For Transport = 1/10 of ₦2,500
= 1/10 × ₦2,500
= ₦250
Total spent = ₦1250 + ₦625 + ₦250
= ₦ 2,215
Miscellaneous = ₦2500 – ₦2,125
= ₦375
ii. The fraction of the salary spent on miscellaneous is
= \(\frac{375}{2500} \\ = \frac{75}{100} \\ = \frac{15}{100} \\ = \frac{3}{20}\)