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JSS1: MATHEMATICS - 2ND TERM
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Algebraic Processes | Week 14 Topics|1 Quiz
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Simplification of Algebraic Expressions | Week 24 Topics|1 Quiz
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Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 34 Topics|1 Quiz
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Simple Equations | Week 41 Topic|1 Quiz
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Simple Equations II | Week 53 Topics|1 Quiz
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Plane Shapes I | Week 65 Topics|2 Quizzes
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Plane Shapes II | Week 77 Topics|1 Quiz
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Plane Shapes III | Week 87 Topics|1 Quiz
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Decimals and Percentages I | Week 92 Topics|1 Quiz
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Decimals and Percentages II | Week 103 Topics|1 Quiz
Lesson 8,
Topic 4
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Area of a Parallelogram
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Topic Content:
- Area of a Parallelogram

Area = base × height
Area = b × h = or bh
If the area is given, then the height, h or the base b may be found as:
Height, h = \( \frac{Area}{Base, \: b} \)
Base, b = \( \frac{Area}{Height, \: h} \)
Example 8.4.1:
Calculate the area of the parallelogram below:

Solution:
Base (b) = 15 cm
Height (h) = 10 cm
Area = bh = 15 cm × 10 cm
= 150 cm2
Example 8.4.2:
A parallelogram has an area of 45 cm2 and its base is 5 cm. Find the height of the parallelogram.

Solution:
Area of parallelogram = 45 cm2
Base of parallelogram = 5 cm
height, h = \( \frac{Area}{base} \\ = \frac{45\:cm^2}{5\:cm}\\ = \frac{45\:cm \: \times \: \not{cm}}{5\: \not{cm}}\\ = \scriptsize 9\:cm\)
The height of the parallelogram is 9 cm