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JSS1: MATHEMATICS - 2ND TERM

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  1. Algebraic Processes | Week 1
    4 Topics
    |
    1 Quiz
  2. Simplification of Algebraic Expressions | Week 2
    4 Topics
    |
    1 Quiz
  3. Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 3
    4 Topics
    |
    1 Quiz
  4. Simple Equations | Week 4
    1 Topic
    |
    1 Quiz
  5. Simple Equations II | Week 5
    3 Topics
    |
    1 Quiz
  6. Plane Shapes I | Week 6
    5 Topics
    |
    2 Quizzes
  7. Plane Shapes II | Week 7
    7 Topics
    |
    1 Quiz
  8. Plane Shapes III | Week 8
    7 Topics
    |
    1 Quiz
  9. Decimal and Percentages I | Week 9
    2 Topics
    |
    1 Quiz
  10. Decimal and Percentages | Week 10
    3 Topics
    |
    1 Quiz



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Screenshot 2022 12 09 at 15.10.15

Area  =   base  x  height
Area =  b  x  h  = or  bh

If the area is given, then the height, h or the base b may be found as:

Height, h = \( \frac{Area}{Base, \: b} \)

Base, b = \( \frac{Area}{Height, \: h} \)

Example 1:

Calculate the area of the parallelogram below:

Screenshot 2022 12 09 at 15.12.36

Solution:

Base (b) = 15cm

Height (h) = 10cm

Area  =   bh   =  15cm  ×  10cm

= 150cm2

Example 2:

A parallelogram has an area of 45cm2 and its base is 5cm. Find the height of the parallelogram.

Screenshot 2022 12 09 at 15.17.10

Solution:

Area of parallelogram = 45cm2

Base of parallelogram   =  5cm

height, h = \( \frac{Area}{base} \\ = \frac{45cm^2}{5cm}\\ = \scriptsize 9cm\)

The height of the parallelogram is 9cm

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