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JSS1: MATHEMATICS - 2ND TERM

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  1. Algebraic Processes | Week 1
    4 Topics
    |
    1 Quiz
  2. Simplification of Algebraic Expressions | Week 2
    4 Topics
    |
    1 Quiz
  3. Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 3
    4 Topics
    |
    1 Quiz
  4. Simple Equations | Week 4
    1 Topic
    |
    1 Quiz
  5. Simple Equations II | Week 5
    3 Topics
    |
    1 Quiz
  6. Plane Shapes I | Week 6
    5 Topics
    |
    2 Quizzes
  7. Plane Shapes II | Week 7
    7 Topics
    |
    1 Quiz
  8. Plane Shapes III | Week 8
    7 Topics
    |
    1 Quiz
  9. Decimals and Percentages I | Week 9
    2 Topics
    |
    1 Quiz
  10. Decimals and Percentages II | Week 10
    3 Topics
    |
    1 Quiz
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Topic Content:

  • Area of a Parallelogram
Screenshot 2022 12 09 at 15.10.15

Area  =   base  ×  height
Area =  b  ×  h  = or  bh

If the area is given, then the height, h or the base b may be found as:

Height, h = \( \frac{Area}{Base, \: b} \)

Base, b = \( \frac{Area}{Height, \: h} \)

Example 8.4.1:

Calculate the area of the parallelogram below:

Screenshot 2022 12 09 at 15.12.36

Solution:

Base (b) = 15 cm

Height (h) = 10 cm

Area  =   bh   =  15 cm  ×  10 cm

= 150 cm2

Example 8.4.2:

A parallelogram has an area of 45 cm2 and its base is 5 cm. Find the height of the parallelogram.

Screenshot 2022 12 09 at 15.17.10

Solution:

Area of parallelogram = 45 cm2

Base of parallelogram   =  5 cm

height, h = \( \frac{Area}{base} \\ = \frac{45\:cm^2}{5\:cm}\\ = \frac{45\:cm \: \times \: \not{cm}}{5\: \not{cm}}\\ = \scriptsize 9\:cm\)

The height of the parallelogram is 9 cm

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