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JSS1: MATHEMATICS - 2ND TERM

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  1. Algebraic Processes | Week 1
    4 Topics
    |
    1 Quiz
  2. Simplification of Algebraic Expressions | Week 2
    4 Topics
    |
    1 Quiz
  3. Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 3
    4 Topics
    |
    1 Quiz
  4. Simple Equations | Week 4
    1 Topic
    |
    1 Quiz
  5. Simple Equations II | Week 5
    3 Topics
    |
    1 Quiz
  6. Plane Shapes I | Week 6
    5 Topics
    |
    2 Quizzes
  7. Plane Shapes II | Week 7
    7 Topics
    |
    1 Quiz
  8. Plane Shapes III | Week 8
    7 Topics
    |
    1 Quiz
  9. Decimals and Percentages I | Week 9
    2 Topics
    |
    1 Quiz
  10. Decimals and Percentages II | Week 10
    3 Topics
    |
    1 Quiz
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Topic Content:

  • Area of a Rectangle

In the previous topic, by counting, we obtained an area of 15 cm2 for a 5 cm by 3 cm rectangle.

Notice also that 5 × 3 = 15

Thus, the area of a rectangle = “Length” × “Width”

Area =  L  ×  W 

Where:

  • L  is the Length
  • W  is the width
Screenshot 2023 12 10 at 08.35.52

If Area is given, then to find L or W, we use the following formula:

Area   =  L    ×    W

  • Length, L = \( \frac{Area}{W} \)
  • Width, W = \( \frac{Area}{L} \)

Example 8.2.1:

Calculate the area of a rectangle of length 50 cm and 30 cm in width.

Solution:

Area   =  Length × Width

= 50 cm   ×     30 cm

= 150 cm2

Example 8.2.2:  

The area of a rectangular carpet is 20 m2. Find the length of the shorter side in metres if the length of the longer side is 4000 mm.

Solution:

Screenshot 2023 12 10 at 08.44.02

First, we have to convert 4000 mm to m (millimetres to metres)

1000 mm   =  1 m

So 4000 mm   = \( \frac{1}{1000} \: \times \: \scriptsize 4000 \\ = \frac{4000}{1000} \\ = \scriptsize 4\: m\)

If A   =   L   ×     W

W = \( \frac{Area}{L} \\ = \frac{20\: m^2}{4\:m} \\ = \frac{20\: m\: \times \: \not{m}}{4\:\not{m}}\\ = \scriptsize 5\:m \)