JSS1: MATHEMATICS - 2ND TERM
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Algebraic Processes | Week 14 Topics|1 Quiz
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Simplification of Algebraic Expressions | Week 24 Topics|1 Quiz
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Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 34 Topics|1 Quiz
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Simple Equations | Week 41 Topic|1 Quiz
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Simple Equations II | Week 53 Topics|1 Quiz
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Plane Shapes I | Week 65 Topics|2 Quizzes
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Plane Shapes II | Week 77 Topics|1 Quiz
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Plane Shapes III | Week 87 Topics|1 Quiz
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Decimals and Percentages I | Week 92 Topics|1 Quiz
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Decimals and Percentages II | Week 103 Topics|1 Quiz
Area of a Rectangle
Topic Content:
- Area of a Rectangle
In the previous topic, by counting, we obtained an area of 15 cm2 for a 5 cm by 3 cm rectangle.
Notice also that 5 × 3 = 15
Thus, the area of a rectangle = “Length” × “Width”
Area = L × W
Where:
- L is the Length
- W is the width

If Area is given, then to find L or W, we use the following formula:
Area = L × W
- Length, L = \( \frac{Area}{W} \)
- Width, W = \( \frac{Area}{L} \)
Example 8.2.1:
Calculate the area of a rectangle of length 50 cm and 30 cm in width.
Solution:
Area = Length × Width
= 50 cm × 30 cm
= 150 cm2
Example 8.2.2:
The area of a rectangular carpet is 20 m2. Find the length of the shorter side in metres if the length of the longer side is 4000 mm.
Solution:

First, we have to convert 4000 mm to m (millimetres to metres)
1000 mm = 1 m
So 4000 mm = \( \frac{1}{1000} \: \times \: \scriptsize 4000 \\ = \frac{4000}{1000} \\ = \scriptsize 4\: m\)
If A = L × W
W = \( \frac{Area}{L} \\ = \frac{20\: m^2}{4\:m} \\ = \frac{20\: m\: \times \: \not{m}}{4\:\not{m}}\\ = \scriptsize 5\:m \)