Back to Course

JSS2: MATHEMATICS - 1ST TERM

0% Complete
0/0 Steps
  1. Properties of Whole Numbers I | Week 1
    4Topics
    |
    2 Quizzes
  2. Properties of Whole Numbers II | Week 2
    4Topics
    |
    2 Quizzes
  3. Properties of Whole Numbers III | Week 3
    4Topics
    |
    1 Quiz
  4. Indices | Week 4
    2Topics
    |
    1 Quiz
  5. Laws of Indices | Week 5
    5Topics
    |
    1 Quiz
  6. Whole Numbers & Decimal Numbers | Week 6
    4Topics
    |
    1 Quiz
  7. Standard Form | Week 7
    3Topics
    |
    1 Quiz
  8. Significant Figures (S.F) | Week 8
    4Topics
    |
    1 Quiz
  9. Fractions, Ratios, Proportions & Percentages I | Week 9
    6Topics
    |
    1 Quiz
  10. Fractions, Ratios, Proportions & Percentages II | Week 10
    4Topics
    |
    1 Quiz
  11. Fractions, Ratios, Proportions & Percentages III | Week 11
    3Topics
    |
    1 Quiz
  12. Approximation & Estimation | Week 12
    1Topic
    |
    1 Quiz
Lesson Progress
0% Complete

Approximations are not exact, but close enough value to the original value that can be used in a calculation. 

For example;

1. If the bus ride takes 57 minutes, one can say it is ‘ a one-hour bus ride”

2. If a cord measures 3.14cm, one can say it is 3cm (which is not the actual value).

The exact number may be greater than or less than the approximation.

Example 1

Round off 285.563  correct to

a. 1s.f

b. 2s.f

c. 1d.p

d. 2 d.p

Solution

a. 285.563 = 300 to 1s.f

b. 285.563 = 290 to 2s.f.

c. 285. 563 = 285.6 to 1d.p

d. 285.563 = 285.56 to 2 d.p

Example 2

Calculate the following and round your answer to the given degree of accuracy.

a. 679.209 + 20.95 (2 d.p) = 700. 159  = 700.16 to 2 d.p

b. 7.63 x 0.6213 (3s.f) = 7.63 x 0.6213  = 4.740519  = 4.74 to 3s.f

c. 792.65 – 37.809 (2 d.p) = 754.841 =  754.84 to 2 d.p

Example 3

As a newspaper editor, state two ways the following numbers will appear in your paper.

a. 59 279 fans attended a football match

b. 7907 new jobs created

Solution

a. 59 279  fans attended a football match can be written as 60 000 to 1s.f.

i.e. 60 thousand fans.

b. 7907 = 8000 new jobs to 1s.f

8  thousand

or

7900 jobs to 2s.f

Using Approximation to Estimate Answers:

Approximations can be used to estimate answers to calculations. This will give one a rough idea of what the real answer should be.

Example 4

Use reasonable approximation to estimate the cost of 402 exercise books at ₦1.85 each.

Cost of 402 exercise books = 402 x ₦1.85

402 – Round off to 1 s.f = 400

₦1.85 – Round off to 1 s.f = 2

Cost of 402 exercise books = 400 x 2 = ₦800

Example 5

Find the approximation values for:

a. \( \frac{407 \: \times \: 196}{35} \)

b. 607 x 68

c. \( \scriptsize 9 \frac{4}{5} \: + \: \scriptsize 8 \frac{1}{7}\)

d. \( \scriptsize 7 \frac{1}{6} \: + \: \scriptsize 2 \frac{3}{5}\)

e. 1218 x 12

Solution

a. \( \frac{407 \: \times \: 196}{35} \)

\( \frac{407 \rightarrow 1 s.f \: \times \: 196 \rightarrow 1 s.f}{35 \rightarrow 1 s.f} \)

= \( \frac{400 \: \times \: 200}{40} \\ \scriptsize = 10 \: \times \: 200 \\ \scriptsize = 2000 \)

b. \(\scriptsize 607 \: \times \: 68 \)

\(\scriptsize 607 \rightarrow 1 s.f \: \times \: 68\rightarrow 1 s.f \\ \scriptsize = 600 \: \times \: 70 \\ \scriptsize = 420000 \)

c. \( \scriptsize 9 \frac{4}{5} \: + \: \scriptsize 8 \frac{1}{7}\)

Compare the denominator and numerators, if the fraction is greater than \( \frac{1}{2} \) or 0.5 we round up, if it’s less than \( \frac{1}{2} \) or 0.5 we round down.

Let’s look at the first fraction

\( \frac{4}{5} \)

To compare with half we multiply the denominator and numerator by 2 and also multiply \( \frac{1}{2} \) by 5.

\( \frac{4 \; \times \; 2}{5 \; \times \; 2} = \frac{8}{10} \)

\( \frac{1 \; \times \; 5}{2 \; \times \; 5} = \frac{1}{10} \)

\( \frac{8}{10}\scriptsize \; is \; greater \; than \; \normalsize \frac{1}{10} \)

Therefore, \( \frac{4}{5}\scriptsize \; is \; greater \; than \; \normalsize \frac{1}{2} \)

so we round up.

\( \scriptsize 9 \frac{4}{5} = 9 + 1 = 10 \)

For the second fraction;

\( \frac{1}{7}\scriptsize\; is \; less \; than \; \normalsize \frac{1}{2} \)

so we round down

\( \scriptsize 8 \frac{1}{7}\) = 8 + 0 = 8

\( \scriptsize \therefore 9 \frac{4}{5} \; + \; \scriptsize 8 \frac{1}{7} = 10 + 8 = 18\)

d. \( \scriptsize 7 \frac{1}{6} \: + \: \scriptsize 2 \frac{3}{5}\)

Comparing the fractions.

\(\frac{1}{6} \rightarrow\) less than  ½ of 6 round down 

\(\frac{3}{5} \rightarrow\) more than half of 5 round up

(7 + 0) – (2 + 1)

= 7 – 3

= 4  

e. \(\scriptsize 1218 \: \times \: 12 \)

\(\scriptsize 1218 \rightarrow 1 s.f \: \times \: 12\rightarrow 1 s.f \\ = \scriptsize 1000 \: \times \: 10 \\ \scriptsize = 10000 \)
back-to-top
error: