Back to Course

JSS2: MATHEMATICS - 1ST TERM

0% Complete
0/0 Steps
  1. Properties of Whole Numbers I | Week 1
    4Topics
    |
    2 Quizzes
  2. Properties of Whole Numbers II | Week 2
    4Topics
    |
    2 Quizzes
  3. Properties of Whole Numbers III | Week 3
    4Topics
    |
    1 Quiz
  4. Indices | Week 4
    2Topics
    |
    1 Quiz
  5. Laws of Indices | Week 5
    5Topics
    |
    1 Quiz
  6. Whole Numbers & Decimal Numbers | Week 6
    4Topics
    |
    1 Quiz
  7. Standard Form | Week 7
    3Topics
    |
    1 Quiz
  8. Significant Figures (S.F) | Week 8
    4Topics
    |
    1 Quiz
  9. Fractions, Ratios, Proportions & Percentages I | Week 9
    6Topics
    |
    1 Quiz
  10. Fractions, Ratios, Proportions & Percentages II | Week 10
    4Topics
    |
    1 Quiz
  11. Fractions, Ratios, Proportions & Percentages III | Week 11
    3Topics
    |
    1 Quiz
  12. Approximation & Estimation | Week 12
    1Topic
    |
    1 Quiz
Lesson Progress
0% Complete

To find the square roots of fractions, reduce fractions to their lowest terms to have perfect squares for both the numerator and denominator.

Example 1

Find the value of the following 

a. \(\sqrt{ \frac{9 }{25}} \)

b. \(\sqrt{ \frac{49 }{4}} \)

c. \(\sqrt{ \frac{18 }{72}} \)

d. \(\sqrt{\scriptsize 2 \normalsize \frac{1 }{4}} \)

e. \(\sqrt{ \frac{72 }{50}} \)

f. \(\sqrt{ \frac{48 }{108}} \)

Solution

a. \(\sqrt{ \frac{9 }{25}} \\ = \frac{\sqrt{9}}{\sqrt{25}}\\ = \frac{3}{5}\)

b. \(\sqrt{ \frac{49 }{4}}\\ = \frac{\sqrt{49}}{\sqrt{4}}\\ = \frac{7}{2}\)

c. \(\sqrt{ \frac{18 }{72}} \\= \frac{\sqrt{2 \: \times \: 9}}{\sqrt{2 \: \times \: 36}} \\ = \frac{\sqrt{9}}{\sqrt{36}}\\= \frac{3}{6} \\ = \frac{1}{2}\)

d. \(\sqrt{\scriptsize 2 \normalsize \frac{1}{4}} \\ = \sqrt{ \frac{9 }{4}} \\= \frac{\sqrt{9}}{\sqrt{4}} \\ = \frac{3}{2} \\ = \scriptsize 1 \normalsize \frac{1}{2}\)

e. \(\sqrt{ \frac{72 }{50}} \\= \frac{\sqrt{2 \: \times \: 36}}{\sqrt{2 \: \times \: 25}}\\ =\sqrt{ \frac{36 }{25}}\\= \frac{6}{5} \\ = \scriptsize 1 \normalsize \frac{1}{5} \)

f. \(\sqrt{ \frac{48}{108}}\\ = \frac{\sqrt{2 \: \times \: 24}}{\sqrt{2 \: \times \: 54}}\\ =\sqrt{ \frac{24 }{54}}\\ =\sqrt{ \frac{12 }{27}}\\ = \frac{\sqrt{4 \: \times \: 3}}{\sqrt{9 \: \times \: 3}}\\ = \sqrt{ \frac{4 }{9}}\\ = \frac{2}{3}\)

back-to-top
error: