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JSS3: MATHEMATICS - 1ST TERM

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  1. Binary Number System I | Week 1
    5 Topics
    |
    1 Quiz
  2. Binary Number System II | Week 2
    6 Topics
    |
    1 Quiz
  3. Word Problems I | Week 3
    4 Topics
    |
    1 Quiz
  4. Word Problems with Fractions II | Week 4
    1 Topic
    |
    1 Quiz
  5. Factorization I | Week 5
    4 Topics
    |
    1 Quiz
  6. Factorization II | Week 6
    3 Topics
    |
    1 Quiz
  7. Factorization III | Week 7
    3 Topics
    |
    1 Quiz
  8. Substitution & Change of Subject of Formulae | Week 8
    2 Topics
    |
    1 Quiz
  9. Simple Equations Involving Fractions | Week 9
    3 Topics
    |
    1 Quiz
  10. Word Problems | Week 10
    1 Topic
    |
    1 Quiz
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Topic Content:

  • Binary Arithmetic Operations – Division

Binary division is straightforward and easy to understand if you follow simple rules.

Similar to the decimal number system, binary division follows the four-step process:

  • Divide
  • Multiply
  • Subtract
  • Bring down

Remember these rules

  • The dividend is divided by the divisor, and the answer is the quotient.
  • Compare the divisor to the first digit in the dividend. If the divisor is the larger number, keep adding digits to the dividend until the divisor is the smaller number. (For example, if calculating 156 ÷ 2, we would compare 2 and 1, note that 2 > 1, and compare 2 to 15 instead.)

Worked Example 2.5.1:

Solve the following:

a. 1110 ÷ 111
b. 1010  ÷ 10
c. 1101001 ÷ 101two

Solution

Divide the following numbers

a. 1110 ÷ 111

Screenshot 2023 08 22 at 02.52.03

Explanation

111 is the divisor, 1110 is the dividend.

Compare the divisor (111) to the dividend (1110) from the first digit.

111 > 1 so we carry on (or add a 0)

111 > 11 so we carry on (or add a 0)

111 = 111, This can be divided. We write 1 in the quotient.

Like standard division, we then multiply the divisor (111) by 1 and then find the remainder by subtracting the result.

The remainder is 0 and the number brought down is 0. What we have now is 00.

We then try and divide again. 111 > 00 so we add a 0 to the quotient.

If we added all the 0’s in the quotient the answer would have been 0010. Removing the first two 00’s does not change the value of the number. 0010two = 10two

Answer = 10two

2nd Method

Note: Both the binary and the decimal systems produce the same result.

1110two = 1 x 23 + 1 x 22 + 1 x 21 + 0 x 20

= 8 + 4 + 2 + 0 = 14

111two = 1 x 22 + 1 x 21 + 1 x 20

= 4 + 2 + 1 = 7

14 ÷ 7 = 2

From the long division method, the result we got was 10two

10two = 1 x 21 + 0 x 20 = 2 + 0 = 2

b. 1010 ÷ 10

Screenshot 2023 08 22 at 02.56.58

Explanation:

10 is the divisor, 1010 is the dividend.

Compare the divisor (10) to the dividend (1010) from the first digit.

10 > 1 so we carry on (or add a 0)

10 = 10. This can be divided. We write 1 in the quotient.

We then multiply the divisor (10) by 1 then find the remainder by subtracting the result. (10 – 10 = 0)

The remainder is 0 and the number brought down is 1. What we have now is 01.

We then try and divide again. 10 > 01. This can’t be divided. We write 0 in the quotient.

We then bring down the next digit which is 0. We now have 10.

We then try and divide again. 10 = 10. This can be divided. We write 1 in the quotient.

Answer = 101two

c. 1101001 ÷ 101two

Screenshot 2023 08 22 at 03.05.18

Answer = 10101two

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