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JSS3: MATHEMATICS - 1ST TERM

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  1. Binary Number System I | Week 1
    5Topics
    |
    1 Quiz
  2. Binary Number System II | Week 2
    6Topics
    |
    1 Quiz
  3. Word Problems I | Week 3
    4Topics
    |
    1 Quiz
  4. Word Problems with Fractions II | Week 4
    1Topic
    |
    1 Quiz
  5. Factorisation I | Week 5
    4Topics
    |
    1 Quiz
  6. Factorisation II | Week 6
    3Topics
    |
    1 Quiz
  7. Factorisation III | Week 7
    3Topics
    |
    1 Quiz
  8. Substitution & Change of Subject of Formulae | Week 8
    2Topics
    |
    1 Quiz
  9. Simple Equations Involving Fractions | Week 9
    3Topics
    |
    1 Quiz
  10. Word Problems | Week 10
    1Topic
    |
    1 Quiz
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This operation is similar to the basic arithmetic subtraction performed on decimal numbers in Maths. Hence, when we subtract 1 from 0, we need to borrow 1 from the next higher order digit, to reduce the digit by 1 and the remainder left here is also 1.

The subtraction of binary numbers is given by:

Binary NumberSubtraction Value
0 – 00
1 – 01
0 – 11 (Borrow 1 from next high order digit)
1 – 10

When you borrow a number during subtraction, it becomes the number of the base you are subtracting from.

For example, in Base 2 if you borrow a number the number you borrow becomes 2.

Subtract the following

i. 1001two from 11001two

Screen Shot 2021 09 14 at 2.54.53 PM

Explanation

1st Column (from right to left) = 1 – 1 = 0. Write 0.

2nd Column = 0 – 0 = 0.Write 0.

3rdColumn = 0 – 0 = 0.Write 0.

4thColumn = 1 – 1 = 0.Write 0.

5thColumn = 1 – 0 = 1.Write 1.

ii. 11011two  from  111010two

Screen Shot 2021 09 14 at 3.04.32 PM

1st Column (from right to left) = 0 is smaller than 1 so we will have to borrow from the 2nd column. Since it is in base 2 any number borrowed is 2. So borrowing two from the second column will give (2 + 0) – 1 = 1

2nd Column = This reduces 1 to 0 in the second column. 0 is smaller than 1 so we have to borrow again from the third column. We now have 2 – 1 = 1

3rd Column = This reduces 0 to -1 in the third column. This too is smaller than 1 so have to borrow from the 4th column. = 2 – 1 – 0 = 1

4th Column = This reduces 1 to 0 in the fourth column. We have to borrow from the 5th column. Remember that since we are subtracting in base 2 the number we borrow is 2. so we have 2 + 0 – 1 = 1

5th Column =This reduces 1 to 0 in the fifth column.We have to borrow from the 5th column.
So we have 2 + 0 – 1 = 1

6th Column = 1 is reduced to 0. The number in the 6th column is 0 so we can ignore it.

Answer = 111112

iii. 1101 -111

Screen Shot 2021 09 14 at 3.22.41 PM

1st Column (from right to left) = 1 – 1 = 0.Write 0.

2nd Column = 0 is smaller than 1 so we have to borrow from the third column. We are subtracting in base 2 so the number we borrow is 2. We therefore have 2 + 0 – 1 = 0

3rd Column = This reduces 1 to 0 in the third column. This too is smaller than 1 so have to borrow from the 4th column. We now have 2 + 0 – 1 = 1

4th Column = This reduces 1 to 0 in the fourth column. We don’t have to write anything down since what we have is 0.

Answer = 1102

iv. 1001two – 1110two

Screen Shot 2020 11 27 at 10.33.41 PM

v. 1111two – 101two

Screen Shot 2020 11 27 at 10.33.50 PM
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