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JSS3: MATHEMATICS - 1ST TERM

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  1. Binary Number System I | Week 1
    5Topics
    |
    1 Quiz
  2. Binary Number System II | Week 2
    6Topics
    |
    1 Quiz
  3. Word Problems I | Week 3
    4Topics
    |
    1 Quiz
  4. Word Problems with Fractions II | Week 4
    1Topic
    |
    1 Quiz
  5. Factorisation I | Week 5
    4Topics
    |
    1 Quiz
  6. Factorisation II | Week 6
    3Topics
    |
    1 Quiz
  7. Factorisation III | Week 7
    3Topics
    |
    1 Quiz
  8. Substitution & Change of Subject of Formulae | Week 8
    2Topics
    |
    1 Quiz
  9. Simple Equations Involving Fractions | Week 9
    3Topics
    |
    1 Quiz
  10. Word Problems | Week 10
    1Topic
    |
    1 Quiz
Lesson 3, Topic 3
In Progress

Solving Combined Products With Sums & Differences

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Example 1

Subtract the product of 9 and 40 from 450 

Solution

You solve them in stages/steps

9 x 40 = 360

450 – 360 = 90

Example 2

Add the negative difference between 27.9 and 35.7 to the product of 27.9 and 35.7

Solution

(27.9 x 35.7)  +  (27.9 – 35.7)

=   996.03 – 7.8

Screen Shot 2021 09 15 at 7.03.22 PM

Ans. 988.23

Example 3

Find the difference between the product of \(\scriptsize 1 \frac{5}{8} \; and \; \frac{4}{5}\) and the difference between \(\scriptsize 1 \frac{5}{8} \; and \; \frac{4}{5}\)

Solution

\(\left [ \scriptsize 1 \frac{5}{8} \; \times \; \frac{4}{5} \right] \; – \; \left[ \scriptsize 1 \frac{5}{8} \; – \; \frac{4}{5} \right] \\ \left [ \frac{13}{8} \; \times \; \frac{4}{5} \right] \; – \; \left[\frac{13}{8} \; – \; \frac{4}{5} \right] \)

\( \frac{13}{10} \; – \; \frac {65 \; – \; 32}{40} \\ = \frac{13}{10} \; – \; \frac{33}{40} \\ = \frac{ 52 \; – \; 33}{40} = \frac{19}{40} \)

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