Back to Course

JSS3: MATHEMATICS - 1ST TERM

0% Complete
0/0 Steps
  1. Binary Number System I | Week 1
    5 Topics
    |
    1 Quiz
  2. Binary Number System II | Week 2
    6 Topics
    |
    1 Quiz
  3. Word Problems I | Week 3
    4 Topics
    |
    1 Quiz
  4. Word Problems with Fractions II | Week 4
    1 Topic
    |
    1 Quiz
  5. Factorization I | Week 5
    4 Topics
    |
    1 Quiz
  6. Factorization II | Week 6
    3 Topics
    |
    1 Quiz
  7. Factorization III | Week 7
    3 Topics
    |
    1 Quiz
  8. Substitution & Change of Subject of Formulae | Week 8
    2 Topics
    |
    1 Quiz
  9. Simple Equations Involving Fractions | Week 9
    3 Topics
    |
    1 Quiz
  10. Word Problems | Week 10
    1 Topic
    |
    1 Quiz



Lesson 10, Topic 1
In Progress

Word Problems Leading to Simple Linear Equations

Lesson Progress
0% Complete

Topic Content:

  • Word Problems Leading to Simple Linear Equations

Worked Example 9.2.1:

Solve the following:

i. If three-quarters of a certain number is 10 more than one-third of the number what is the number.

ii. A man spends one-third of his monthly salary earning on projects and one-quarter of the remainder on household needs. If he has N15000 left how much does he receive in a month?

iii. Think of a number, treble it, then divide by 4, the result is 12 more than the original number, find the number.

iv. When 12  is subtracted from a number, and the answer is divided into 10,  the result obtained is one-quarter of the original number. Find the number.

v. A mother is four times as old as her daughter. If their age difference is three decades, find the ages of the mother and her daughter.

i. If three-quarters of a certain number is 10 more than one-third of the number what is the number?

Solution

Let the number be x

⇒ \( \frac{3}{4}\scriptsize x = 10 \: +\: \normalsize \frac{1}{3}\scriptsize x \)

Take L.C.M

⇒ \( \frac{3x}{4} \: + \: \frac{1x}{3} \)

Cross multiply

⇒ \( \scriptsize 3x \: \times \: 3 = 4(30 \: + \: x) \)

⇒ \( \scriptsize 9x = 120 \: + \: 4x \)

Take like terms

⇒ \( \scriptsize 9x \: – \:4x = 120 \)

⇒ \( \scriptsize 5x = 120 \)

Divide both sides by 5

⇒ \( \frac{ 5x}{5} = \frac{120}{5} \)

⇒ \( \frac{ \not{5}x}{\not{5}} = \frac{120}{5} \)

\( \scriptsize x = 24 \)

ii.   A man spends one-third of his monthly salary earning on projects and one-quarter of the remainder on household needs. If he has N15000 left how much does he receive in a month?

Solution

Let the income be x

 

You are viewing an excerpt of this Topic. Subscribe Now to get Full Access to ALL this Subject's Topics and Quizzes for this Term!

Click on the button "Subscribe Now" below for Full Access!

Subscribe Now

Note: If you have Already Subscribed and you are seeing this message, it means you are logged out. Please Log In using the Login Button Below to Carry on Studying!

Responses

Your email address will not be published. Required fields are marked *

error: Alert: Content selection is disabled!!