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SS1: CHEMISTRY - 1ST TERM

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  1. Introduction to Chemistry and Laboratory Apparatus | Week 1
    5 Topics
    |
    1 Quiz
  2. Nature of Matter | Week 2
    3 Topics
    |
    1 Quiz
  3. Separation Techniques I | Week 3
    1 Topic
  4. Separation Techniques II | Week 4
    5 Topics
    |
    1 Quiz
  5. Particulate Nature of Matter I | Week 5
    5 Topics
    |
    1 Quiz
  6. Particulate Nature of Matter II | Week 6
    9 Topics
    |
    1 Quiz
  7. Symbols, Formulae & Oxidation Number | Week 7
    7 Topics
    |
    1 Quiz
  8. Laws of Chemical Combination | Week 8
    4 Topics
    |
    1 Quiz
  9. Chemical Equation & Chemical Combination (Chemical Bonding) I | Week 9
    4 Topics
    |
    1 Quiz
  10. Chemical Combination (Chemical Bonding) II | Week 10
    4 Topics
    |
    1 Quiz
  11. Chemical Combination (Chemical Bonding) III & Shapes of Covalent Molecules | Week 11
    3 Topics
    |
    1 Quiz
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Topic Content:

  • Relative Molecular Mass

The relative molecular mass of an element or a compound is the number of times the average mass of one molecule of it is heavier than one-twelfth the mass of one atom of carbon-12.

\(\scriptsize Relative \:Molecular \:Mass = \normalsize \frac{mass \: of \: 1 \: molecule \: of \: substance}{\frac{1}{12} \: \times \: mass \: of \: Carbon-12 } \)

The relative molecular mass of an element or compound is the sum of the relative atomic mass of the atoms in one molecule of that substance.

Example 6.5.1:

Calculate the relative molecular mass (RMM) of the following compounds.

(a) CaCO3 (b) HNO3 (c) KCl.

(Ca = 40, C = 12, O = 16, H = 1, N =14, K = 39, Cl = 35.5)

Solution:

(a) CaCO3

40 + 12 + (16 × 3)

40 + 12 + 48 = 100

(b) HNO3

1 + 14 + (16 × 3)

15  + 48 =   63

(c) KCl

39 + 35.5 = 74.5

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