Back to Course

SS1: MATHEMATICS - 3RD TERM

0% Complete
0/0 Steps
  1. Geometry (Triangles & Polygons) I
    2 Topics
    |
    1 Quiz
  2. Geometry (Triangles & Polygon) II
    2 Topics
    |
    1 Quiz
  3. Geometry (Triangles & Polygon) III
    3 Topics
    |
    1 Quiz
  4. Trigonometry I
    2 Topics
  5. Trigonometry II
    3 Topics
    |
    1 Quiz
  6. Trigonometry III
    3 Topics
    |
    1 Quiz
  7. Mensuration | Plane Shapes
    3 Topics
    |
    1 Quiz
  8. Mensuration | Arcs, Sectors and Segments of Circles
    4 Topics
    |
    1 Quiz
  9. Mensuration | Solid Shapes
    8 Topics
    |
    1 Quiz
  10. Statistics
    2 Topics
    |
    1 Quiz
  • excellence
Lesson Progress
0% Complete

Topic Content:

  • Area of Sector
Area of sector

Recall, the area of a circle is given as \( \scriptsize \pi r^2 \)

In general, the area of a sector of a circle is proportional to the angle of the sector as shown in the diagram above, i.e. the area of the sector XOY is \( \frac{\theta}{360^o} \)of the whole circle, that is:

Area of Sector XOY = \( \frac {\theta}{360} \scriptsize \: \times \: \pi r^2 \)

Example 8.2.1:

A pie chart is divided into four sectors as shown in the diagram below. Each sector represents a percentage of the whole. The two larger sectors are equal, and each represents X%. What is the angle subtended by one of those larger sectors? (WAEC)

Screen Shot 2021 11 26 at 4.52.27 AM

Solution:

Note: x% + x% + 21 + 9 = 100%

i.e. 2x% = 100 – 30

i.e. x% = \( \frac{70}{2}\)= 35%

x% = 35%

by proportions:

  • 35% ≡ x°
  • 100% ≡ 360º

x° = \( \scriptsize 360^o \: \times \: \normalsize \frac{35}{100} \\ = \scriptsize 36\not{0}^{o} \: \times \: \normalsize \frac{35}{10\not{0}} \\ = \scriptsize 18^o \: \times \: \normalsize \frac{35}{5} \\ = \scriptsize 18^o \: \times \: 7^o \\ = \scriptsize 126^o \)

Example 8.2.2:

In the diagram below, ABCD is a rhombus with dimensions as shown. BXD is a circular arc with centre A. Calculate the area of the blue shaded section to the nearest cm2.

Screenshot 2025 05 08 at 05.35.30

Solution

Area of shaded section = Area of rhombus – Area of sector

Area of rhombus = \(\scriptsize ab\: sin \: \theta \\ = \scriptsize a^2\: sin \: \theta\)

= 9 × 9 × 

🔒 KOFA STUDY
🔒

Unlock This Topic

This topic is available to course subscribers.

Subscribe to continue this course.

  • 📚 Continue this topic
  • 📝 Attempt quizzes
  • 📈 Track your learning progress
  • 🪙 Earn KofaCoins
🚀 Unlock every topic, quiz and Kofa Arcade challenge in this course.

Like this content

Subscribe
Notify of
guest
4 Comments
Oldest
Newest
Inline Feedbacks
View all comments
Princess Omowunmi
Princess Omowunmi
05/07/2023 10:38 PM

Love 💕 it

Covenant Youths
Reply to  Princess Omowunmi
19/07/2024 12:08 PM

actually i love it also

avatar
Covenant Youths
19/07/2024 12:10 PM

hi guys

Covenant Youths
19/07/2024 12:11 PM

are you there

4
0
Would love your thoughts, please comment.x
()
x
×
×
Loading Kofa Arcade
Getting Game Ready...