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SS1: MATHEMATICS - 3RD TERM

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  1. Geometry (Triangles & Polygon) I | Week 1
    1 Topic
  2. Geometry (Triangles & Polygon) II | Week 2
    2 Topics
    |
    1 Quiz
  3. Geometry (Triangles & Polygon) III | Week 3 & 4
    2 Topics
    |
    1 Quiz
  4. Trigonometry I | Week 5 & 6
    2 Topics
  5. Trigonometry II
    3 Topics
    |
    1 Quiz
  6. Trigonometry III
    3 Topics
    |
    1 Quiz
  7. Mensuration (Plane Shapes) | Week 8
    1 Topic
    |
    1 Quiz
  8. Mensuration II
    4 Topics
    |
    1 Quiz
  9. Mensuration III | Solid Shapes
    8 Topics
    |
    1 Quiz
  10. Statistics | Week 9
    2 Topics
    |
    1 Quiz
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Topic Content:

  • Solving Right Angle Triangles
Screenshot 2024 05 17 at 12.29.42
Fig. 4.1.1
Screenshot 2024 05 17 at 12.38.18
Fig. 4.1.2

Recall in trigonometric ratios, the Hypotenuse is unique, facing the right angle (90º), however, the Opposite and Adjacent sides depend on the angle (θ) under consideration. 

For example, side AB is Adjacent in Fig. 4.1.1 while it is the Opposite side in Fig. 4.1.2.

In Figure 4.1.1 and Figure 4.1.2:

Sin B = \( \frac{Opp}{Hyp} = \frac{b}{a} \)

Cos B = \( \frac{Adj}{Hyp} = \frac{c}{a} \)

Tan B = \( \frac{Opp}{Adj} = \frac{b}{c} \)

Sin C = \( \frac{Opp}{Hyp} = \frac{c}{a} \)

Cos C = \( \frac{Adj}{Hyp} = \frac{b}{a} \)

Tan C = \( \frac{Opp}{Adj} = \frac{c}{b} \)

In ΔABC, B and C are complementary angles (i.e. B + C = 90º)

As seen above, if B = θ, then C = 90 – θ

Therefore,

 

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Dp
Dp
3 years ago

Good

2 years ago

Great

irene Ahuruonye
8 months ago

it is hard at first but its all good 🤓

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