SS1: PHYSICS – 1ST TERM
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Introduction to Physics | Week 14 Topics|1 Quiz
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Measurement I | Week 23 Topics|1 Quiz
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Measurement II | Week 36 Topics|1 Quiz
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Motion | Week 45 Topics|1 Quiz
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Velocity-Time Graph | Week 54 Topics|1 Quiz
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Causes of Motion | Week 65 Topics|1 Quiz
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Work, Energy & Power | Week 73 Topics
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Energy Transformation / Power | Week 83 Topics|1 Quiz
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Heat Energy | Week 95 Topics|1 Quiz
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Linear Expansion | Week 107 Topics|1 Quiz
Angular Speed and Velocity
Topic Content:
- Angular Speed and Velocity
When a stone is tied to the end of a string or rope and whirled around, the stone moves in a circular path as shown in the diagram below.

Suppose that as the stone is being whirled around, it moves from point M to N, in t seconds, so that the radius OM sweeps through an angle θ at the same time.
As the stone moves around the circular path and sweeps through angle θ , the stone moves with angular velocity, \(\scriptsize \omega \)
Angle \(\scriptsize \hat{MON} = \theta ,\)the angular velocity of motion, \( \scriptsize \omega \)can be defined as;
\(\scriptsize \omega = \normalsize \frac{\theta}{t}\)................. (1)
We can say that the angular velocity, \(\scriptsize \omega , \)is the angle turned through, with respect to time.
Recall that linear velocity, v is given by the formula:
\( \scriptsize v = \normalsize \frac{s}{t} \)................ (2)
where s is the length of the arc MN.
Comparing equations 1 and 2, instead of using linear displacement in 1, we used angular displacement θ .

The image illustrates the relationship between the radius and the central angle θ in radians.
We define the rotation angle θ to be the ratio of the arc length to the radius of curvature:
The formula is \(\scriptsize \theta = \normalsize \frac{s}{r} \)
Therefore,
s =
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thank you
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