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SS1: PHYSICS – 1ST TERM

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  1. Introduction to Physics
    6 Topics
    |
    1 Quiz
  2. Measurement I
    8 Topics
    |
    1 Quiz
  3. Measurement II
    8 Topics
    |
    1 Quiz
  4. Motion
    8 Topics
    |
    1 Quiz
  5. Rectilinear Acceleration and Motion Graphs
    8 Topics
    |
    1 Quiz
  6. Causes of Motion
    7 Topics
    |
    1 Quiz
  7. Work and Power
    5 Topics
    |
    1 Quiz
  8. Energy Transformation and Power
    5 Topics
    |
    1 Quiz
  9. Heat Energy
    8 Topics
    |
    1 Quiz
  10. Linear Expansion
    8 Topics
    |
    1 Quiz
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Lesson 3, Topic 6
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Dimensions of Physical Quantities

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Topic Content:

  • Meaning of Dimensions of a physical quantity
  • Quick Recall — Laws of Indices
  • Fundamental Dimensions
  • Dimensions of Derived Quantities
  • Summary of Common Dimensions
  • Using Dimensional Analysis to Check an Equation
  • Key Points

What are Dimensions of a Physical Quantity?

The dimensions of a physical quantity show how that quantity is related to fundamental quantities such as mass, length and time.

In dimensional analysis, the dimensions of mass , length and time are represented by the capital letters M , L and T , respectively.

Quick Recall — Laws of Indices

Before working with dimensions, recall some important laws of indices. These rules will help us simplify dimensional expressions.

⇒ \( \scriptsize a^m \times a^n = a^{m+n}\)

⇒ \(\frac{a^m}{a^n} \scriptsize = a^{m-n}\)

⇒ \( \scriptsize (a^m)^n = a^{mn}\)

⇒ \( \scriptsize a^{-n} = \normalsize \frac{1}{a^n}\)

⇒ \( \scriptsize a^0 = 1\)

⇒ \(\scriptsize a^{\frac{1}{n}} \scriptsize = \sqrt[n]{a}\)

In dimensional analysis, these same rules are used when multiplying, dividing or raising dimensions to powers.

Derived quantities can be expressed in terms of these fundamental dimensions. For example, velocity depends on length and time, while force depends on mass, length and time.

Dimensions of Derived Quantities:

Some common derived quantities and their dimensions are shown below.

Velocity

Velocity = \(\frac{distance}{time}\)

Therefore:

\(\scriptsize [V] = \normalsize \frac{L}{T} \scriptsize = LT^{-1}\)

Momentum

Momentum = Mass × Velocity

\(\scriptsize [p] = M \times LT^{-1} = MLT^{-1}\)

Acceleration

Acceleration = \(\frac{velocity}{time}\)

\(\scriptsize [a] = \normalsize \frac{LT^{-1}}{T} \\ \scriptsize = L \: \times \: T^{-1} \: \times \: T^{-1} \\ \scriptsize = L \: \times \: T^{-1 \: – \: 1} \\ \scriptsize = LT^{-2}\)

Force

Force = Mass 

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Chike Amadi
15/03/2023 5:02 AM

Nice leaaon. Thanks a lot

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Precious
Precious
15/09/2023 2:32 AM

Please do a video lessons

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