SS1: PHYSICS – 1ST TERM
-
Introduction to Physics6 Topics|1 Quiz
-
Measurement I8 Topics|1 Quiz
-
Measurement II8 Topics|1 Quiz
-
Motion8 Topics|1 Quiz
-
Rectilinear Acceleration and Motion Graphs8 Topics|1 Quiz
-
Causes of Motion7 Topics|1 Quiz
-
Work and Power5 Topics|1 Quiz
-
Energy Transformation and Power5 Topics|1 Quiz
-
Heat Energy8 Topics|1 Quiz
-
Linear Expansion8 Topics|1 Quiz
Dimensions of Physical Quantities
Topic Content:
- Meaning of Dimensions of a physical quantity
- Quick Recall — Laws of Indices
- Fundamental Dimensions
- Dimensions of Derived Quantities
- Summary of Common Dimensions
- Using Dimensional Analysis to Check an Equation
- Key Points
What are Dimensions of a Physical Quantity?
The dimensions of a physical quantity show how that quantity is related to fundamental quantities such as mass, length and time.
In dimensional analysis, the dimensions of mass , length and time are represented by the capital letters M , L and T , respectively.
Quick Recall — Laws of Indices
Before working with dimensions, recall some important laws of indices. These rules will help us simplify dimensional expressions.
⇒ \( \scriptsize a^m \times a^n = a^{m+n}\)
⇒ \(\frac{a^m}{a^n} \scriptsize = a^{m-n}\)
⇒ \( \scriptsize (a^m)^n = a^{mn}\)
⇒ \( \scriptsize a^{-n} = \normalsize \frac{1}{a^n}\)
⇒ \( \scriptsize a^0 = 1\)
⇒ \(\scriptsize a^{\frac{1}{n}} \scriptsize = \sqrt[n]{a}\)
In dimensional analysis, these same rules are used when multiplying, dividing or raising dimensions to powers.
Derived quantities can be expressed in terms of these fundamental dimensions. For example, velocity depends on length and time, while force depends on mass, length and time.
Dimensions of Derived Quantities:
Some common derived quantities and their dimensions are shown below.
Velocity
Velocity = \(\frac{distance}{time}\)
Therefore:
\(\scriptsize [V] = \normalsize \frac{L}{T} \scriptsize = LT^{-1}\)
Momentum
Momentum = Mass × Velocity
\(\scriptsize [p] = M \times LT^{-1} = MLT^{-1}\)
Acceleration
Acceleration = \(\frac{velocity}{time}\)
\(\scriptsize [a] = \normalsize \frac{LT^{-1}}{T} \\ \scriptsize = L \: \times \: T^{-1} \: \times \: T^{-1} \\ \scriptsize = L \: \times \: T^{-1 \: – \: 1} \\ \scriptsize = LT^{-2}\)
Force
Force = Mass
Unlock This Topic
This topic is available to course subscribers.
Subscribe to continue this course.
- 📚 Continue this topic
- 📝 Attempt quizzes
- 📈 Track your learning progress
- 🪙 Earn KofaCoins


Nice leaaon. Thanks a lot
Please do a video lessons