Experiment to Determine Apparent Cubic Expansivity of Liquid
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- Experiment to Determine Apparent Cubic Expansivity of Liquid
Experiment to Determine Apparent Cubic Expansivity of Liquid:
- Weigh a clean dry densityDensity is the measurement of how tightly a material is packed together i.e. how closely the particles are packed in the material. The tighter the material is packed the more its... More bottle and record mass, M1.
- Fill the bottle with liquid whose apparent cubic expansivity is required, replace the stopper, and dry
- Weigh the bottle and liquid, M2
- Suspend the density bottle in a water bath and record the initial temperature of the water bath, \( \scriptsize \theta_1\)
- Heat the water until it reaches boiling point, some liquid will be expelled through the orifice (opening) of the bottle stopper.
- Continue heating the water bath until no liquid is expelled from the space around the stopper.
- Note and record the final temperature of the water bath, \( \scriptsize \theta_2\)
- Remove the bottle from the bath and reweigh, M3
The Apparent cubic expansivity is calculated as follows:
Mass of empty bottle = M1
Mass of bottle and liquid = M2
Final mass of bottle and liquid = M3
Initial temperature of water = \( \scriptsize \theta_1\)
Final temperature of water = \( \scriptsize \theta_2\)
Mass of liquid expelled = M2 – M3
Mass of remaining liquid = M3 – M1
Apparent expansivity = \(\scriptsize γ_α\)
Since mass is proportional to volume,
Apparent cubic expansivity,
\( \scriptsize γ_a = \normalsize \frac {mass\: of\: liquid\: expelled}{mass\: of\: liquid\: remaining \: \times \:temperature\: rise}\)\( γ_a = \frac {M_2 \:- \:M_3}{(M_3\: – \:M_1) \: \times \: (\theta_2\: – \:\theta_1) }\)
Example 1.3.1:
A density bottle contains 44.25 g of a liquid at 0°C and 42.02 g at 50°C. Calculate the real cubic expansivity of the liquid. (Linear expansivity of glass = 1.0 × 10-5K-1)
Solution
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can someone please explain the third example, its very confusing
This is very helpful and I aced my test