Back to Course

SS1: PHYSICS – 3RD TERM

0% Complete
0/0 Steps
  1. Production of Electric Current | Week 1
    6 Topics
    |
    1 Quiz
  2. Electric Current | Week 2
    5 Topics
    |
    1 Quiz
  3. Electrical Resistance of a Conductor | Week 3
    5 Topics
    |
    1 Quiz
  4. Particulate Nature of Matter | Week 4
    5 Topics
    |
    1 Quiz
  5. Crystalline and Non-crystalline Substances | Week 5
    3 Topics
    |
    1 Quiz
  6. Elastic Properties of Solids | Week 6 & 7
    4 Topics
    |
    1 Quiz
  7. Fluids at Rest & in Motion | Week 8 & 9
    6 Topics
    |
    1 Quiz
  8. Solar Collector
    3 Topics
    |
    1 Quiz



  • Follow us

Lesson Progress
0% Complete

Resistors can be connected in two ways in a circuit. The connections are:

1. Connection of resistors in series.

2. Connection of resistors in parallel.

Resistance in Series:

When three resistors, R1, R2 and R3 are connected in series, i.e. one end to another end to form a linear network, the same amount of current flows through them when they are connected to a source of e.m.f.

The total resistance, R (effective resistance) is given by V = IReff

resistance in series 2

From the circuit diagram, the voltage V is connected across the three resistors. This voltage is shared across each of the resistors.
Remember that the voltages drop across each of the resistors are different because the resistances of the resistors are different. Therefore, Let the Voltage of the cell connected across the three resistors be V.

Let the voltage drop across resistor R1 be V1.

Let the voltage drop across resistor R2 be V2, also,

Let the voltage drop across resistor R3 be V3.

Therefore the total voltage can then be found;

V = V1 + V2 + V3

IReff = \( \scriptsize \pm R1 \pm R2 \pm R3 \)

Using Ohm’s law:

V = IReff

V1 = IR1

V2 = IR2

V3 = IR3

Since the same current flows through the resistors, 

Then IReff = IR1 + IR2 + IR3

Factorising I we then have:

IReff = I(R1 + R2 + R3)

We then divide both sides by I

= \( \frac {IR_{eff}}{I} = \frac {I \left ( R_1 + R_2 + R_3 \right)}{I} \)

∴  Reff = R1 + R2 + R3

The total resistance is greater than the highest resistance in the circuit.

Example 1:

Two resistors of value 3Ω and 5Ω are connected in series. Find the effective resistance.

resistance series

Solution:

Rtotal = R1 + R2

= 3Ω + 5Ω

= 8Ω

Example 2:

From the diagram below, calculate the total resistance of the circuit.

Drawing2

Solution:

From the diagram, R1 = 8 Ω, R2 = 5 Ω, R3 = 13 Ω.

Formula: Rtotal = R1 + R2 + R3

Substitution:  Rtotal = 8Ω + 5Ω + 13Ω

⇒ Total resistance of the circuit Rtotal = 26Ω

Example 3:

7 Ohms, 9 Ohms and R resistors are connected in series. If the total resistance of the circuit is 45, calculate the value of the third resistor R.

Solution:

Data given in the question:

R1 = 7 ohms, R2 = 9 ohms, R3 = ?

Formula: Rtotal = R1 + R2 + R3

Substitute the values:

45 = 7 + 9 + R3.

⇒ 45 = 16 + R3

Make R3 the subject:    

R3 = 45 – 16.

⇒ R = 29 Ω

Responses

Your email address will not be published. Required fields are marked *

error: