Calculations on Solubility

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Calculations on Solubility

Example 2.5.1:

30 cm³ of a saturated solution of a salt NaX was dissolved in water at 25°C, was evaporated to dryness and only 2.5 g of solid was left. Calculate the solubility of the salt in water at 25°C in moles/dm³(Na = 23, X = 19)

Solution

30 cm³ of saturated solution contains 2.5 g

1000 cm³ of the solution will contain

\( \frac{1000\:cm^3}{30\:cm^3} \: \times \: \frac{2.5g}{1} \\ \normalsize = \scriptsize 83.3\: g/dm^3 \)

Solubility in mol/dm³ = \( \frac{Solubility\: in \: g/dm^3}{Molar\:Mass} \)

Molar mass of NaX = 23 + 19 = 42 g/mol

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