Back to Course

SS2: CHEMISTRY - 2ND TERM

0% Complete
0/0 Steps
  1. Water & Solution I | Week 1
    10 Topics
    |
    1 Quiz
  2. Water, Solution and Solubility | Week 2 & 3
    9 Topics
    |
    1 Quiz
  3. Air | Week 4
    4 Topics
    |
    1 Quiz
  4. Pollution | Week 5
    6 Topics
    |
    1 Quiz
  5. Rate of Chemical Reaction | Week 6 & 7
    6 Topics
    |
    1 Quiz
  6. Energy and Energy Effect I | Week 8 & 9
    7 Topics
    |
    1 Quiz
  7. Energy and Energy Effect II | Week 10 & 11
    6 Topics
    |
    1 Quiz
  8. Chemical Equilibrium | Week 12
    8 Topics
    |
    1 Quiz
  • excellence
  • Follow

Lesson Progress
0% Complete

Topic Content:

  • Calculations on Solubility

Example 2.5.1:

30 cm3 of a saturated solution of a salt NaX was dissolved in water at 25°C, was evaporated to dryness and only 2.5 g of solid was left. Calculate the solubility of the salt in water at 25°C in moles/dm3 (Na = 23, X = 19)

Solution

30 cm3 of saturated solution contains 2.5 g 

1000 cm3 of the solution will contain

\( \frac{1000\:cm^3}{30\:cm^3} \: \times \: \frac{2.5g}{1} \\ \normalsize = \scriptsize 83.3\: g/dm^3 \)

Solubility in mol/dm3 = \( \frac{Solubility\: in \: g/dm^3}{Molar\:Mass} \)

Molar mass of NaX = 23 + 19 = 42 g/mol 

 

You are viewing an excerpt of this Topic. Subscribe Now to get Full Access to ALL this Subject's Topics and Quizzes for this Term!

Click on the button "Subscribe Now" below for Full Access!

Subscribe Now

Note: If you have Already Subscribed and you are seeing this message, it means you are logged out. Please Log In using the Login Button Below to Carry on Studying!

avatar

Responses

Your email address will not be published. Required fields are marked *