Back to Course

SS2: MATHEMATICS - 2ND TERM

0% Complete
0/0 Steps
  • excellence
  • Follow

Lesson 6, Topic 2
In Progress

Addition and Subtraction of Algebraic Fractions

Lesson Progress
0% Complete

Topic Content:

  • Addition and Subtraction of Algebraic Fractions

Example 6.2.1:

Simplify the following:

a. \( \frac{4}{5m} \: + \: \frac{5}{6m} \)

b. \( \frac{2}{x\:+\:1} \: + \: \frac{3}{2x\:+\:3} \)

c. \( \frac{2}{x\:+\:1} \: + \: \frac{3}{x^2\:-\:1} \)

d. \( \frac{m}{n} \: + \: \frac{m\:-\:1}{5n} \: - \: \frac{m\:-\:2}{10n}\)

e. \( \frac{x\:+\:4}{x^2 \: - \: 3x} \: - \: \frac{x \: - \: 1}{9 \: - \: x^2} \)

Solution

a. \( \frac{4}{5m} \: + \: \frac{5}{6m} \)

First step is to find the L.C.M of the denominators

L.C.M = 30mn

⇒ \( \frac{4}{5m} \: + \: \frac{5}{6n}\\ = \frac{24n \: + \: 25m}{30mn} \)

b. \( \frac{2}{x\:+\:1} \: + \: \frac{3}{2x\:+\:3} \)

⇒ \( \frac{2(2x\:+\:3)\:+\: 3(x \:+\:1)}{(x \:+\:1)(2x\:+\:3)} \)

⇒ \( \frac{4x\:+\:6\:+\: 3x \:+\:3}{(x \:+\:1)(2x\:+\:3)} \)

⇒ \( \frac{7x\:+\:9}{(x \:+\:1)(2x\:+\:3)} \)

c. \( \frac{2}{x\:+\:1} \: - \: \frac{3}{x^2\:-\:1} \)

⇒ \( \frac{2}{x\:+\:1} \: - \: \frac{3}{(x\:+\:1)(x\:-\:1)} \)

⇒ \( \frac{2(x\:-\:1) \: - \: 3}{(x\:+\:1)(x\:-\:1)} \)

⇒ \( \frac{2x\:-\:2 \: - \: 3}{(x\:+\:1)(x\:-\:1)} \)

⇒ \( \frac{2x\:-\: 5}{(x\:+\:1)(x\:-\:1)} \)

d. ...

 

You are viewing an excerpt of this Topic. Subscribe Now to get Full Access to ALL this Subject's Topics and Quizzes for this Term!

Click on the button "Subscribe Now" below for Full Access!

Subscribe Now

Note: If you have Already Subscribed and you are seeing this message, it means you are logged out. Please Log In using the Login Form Below to Carry on Studying!

Subscribe
Notify of
guest
0 Comments
Oldest
Newest
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x