Topic Content:
- Algebraic Solution
- Substitution Method
- Elimination Method
Algebraic Solution:
This involves:
- Substitution Method
- Elimination Method
Substitution Method:
Example 8.1.1:
Use the substitution method to solve the following pairs of simultaneous equations
(a) q + 2r = 8; r – \( \frac{q}{2} \) + 1 = 0
(b) y – \( \frac{x}{4} \) = 3; 3y + x = 23
Solution:
(a) q + 2r = 8; r – \( \frac{q}{2} \) + 1 = 0
⇒ Simplify \( \scriptsize r \: – \: \normalsize \frac {q}{2} \scriptsize \: + \: 1 = 0 \)
⇒ Re-write as \( \scriptsize r\: -\: \normalsize \frac {q}{2} \scriptsize = \: -1 \)
Multiply both sides by 2
⇒ 2r – q = -2 …………(1)
From the question we write down the other equation
⇒ q + 2r = 8 …………(2)
Make q the subject
⇒ q = 8 – 2r ………….(3)
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