Topic Content:
- Application of Equations of Motion
Let’s list the four equations of motion again;
(1) v = u + at
(2) s = \(\scriptsize ut \: +\: \normalsize \frac{at^2}{2} \)
(3) \( \scriptsize v^2 = u ^2 \: + \: 2as \)
(4) s = \( \frac{u\: + \:v}{2} \scriptsize\: \times\: t \)
Also, the equations of motion for the uniformly accelerated bodies;
(1) v = \( \scriptsize u \pm gt \)
(2) h = \( \scriptsize ut \pm \normalsize \frac{1}{2} \scriptsize gt^2 \)
(3) v2 = \( \scriptsize u^2 \pm 2gh \)
Example 2.3.1:
A bike travels from rest and accelerates uniformly to a velocity of 20 ms-1 in 5 seconds. Calculate the distance travelled.
Solution:
u = 0, v = 20 ms-1, t = 5 s
s = \( \frac{u \: + \: v}{2} \scriptsize \times t \)
s = \( \frac{0 \: + \: 20}{2} \scriptsize \times 5 \)
= 10 × 5
s = 50 m
Example 2.3.2:
A ball thrown vertically upward with an initial velocity of 40 m/s has a deceleration of 10m/s2 Calculate its:
(a) velocity after 2.5 s and
(b) time to reach maximum height. (g = 10 m/s2.)
Solution:
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