Lesson 2, Topic 3
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# Application of Equations of Motion

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### Topic Content:

• Application of Equations of Motion

Let’s list the four equations of motion again;

(1) v = u + at

(2) s = $$\scriptsize ut \: +\: \normalsize \frac{at^2}{2}$$

(3) $$\scriptsize v^2 = u ^2 \: + \: 2as$$

(4) s = $$\frac{u\: + \:v}{2} \scriptsize\: \times\: t$$

Also, the equations of motion for the uniformly accelerated bodies;

(1) v = $$\scriptsize u \pm gt$$

(2) h = $$\scriptsize ut \pm \normalsize \frac{1}{2} \scriptsize gt^2$$

(3) v2 = $$\scriptsize u^2 \pm 2gh$$

### Example 2.3.1:

A bike travels from rest and accelerates uniformly to a velocity of 20 ms-1 in 5 seconds. Calculate the distance travelled.

Solution:

u = 0, v = 20 ms-1, t = 5 s

s = $$\frac{u \: + \: v}{2} \scriptsize \times t$$

s = $$\frac{0 \: + \: 20}{2} \scriptsize \times 5$$

= 10 × 5

s = 50 m

### Example 2.3.2:

A ball thrown vertically upward with an initial velocity of 40 m/s has a deceleration of 10m/s2 Calculate its:
(a) velocity after 2.5 s and
(b) time to reach maximum height. (g = 10 m/s2.)

Solution:

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