SS2: PHYSICS - 1ST TERM
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Scalars & Vectors | Week 15 Topics|1 Quiz
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Equations of Motion | Week 23 Topics|1 Quiz
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Projectile | Week 35 Topics|1 Quiz
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Equilibrium of Forces I | Week 44 Topics
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Equilibrium of Forces II | Week 54 Topics|1 Quiz
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Stability of a Body | Week 64 Topics|1 Quiz
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Simple Harmonic Motion (SHM) | Week 74 Topics
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Speed, Velocity & Acceleration & Energy of Simple Harmonic Motion | Week 85 Topics|1 Quiz
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Linear Momentum | Week 96 Topics|1 Quiz
Condition of Equilibrium Under the Action of Non-Parallel Coplanar Forces
Topic Content:
- Condition of Equilibrium Under the Action of Non-Parallel Coplanar Forces
The conditions of equilibrium under the action of non-parallel coplanar forces are:
1. Forces: The vector sum of all the forces acting on a body must be zero i.e.
(i) The algebraic sum of the horizontal components must be zero i.e. ∑Fx = 0
(ii) The algebraic sum of the vertical components of the forces must be zero i.e. ∑Fy = 0
2. Moments: The algebraic sum of the moments of all the forces about any axis perpendicular to the plane of the forces must be zero.
Example 5.2.1:
In the diagram below an object of mass 500 kg is kept in equilibrium by three cables. Find the tension in each of the three cables. (g = 9.8 ms-2 )

Solution:
Tension in cable 3 can be found easily
T3 = mg
∴ T3 = 500 × 9.8 = 4900 N (in the negative direction)
To find T1 and T2 , since the object is in equilibrium ∑Fx = 0 and ∑Fy = 0
The horizontal component
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I Got quite confused