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SS2: PHYSICS - 1ST TERM

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  1. Scalars & Vectors | Week 1
    5 Topics
    |
    1 Quiz
  2. Equations of Motion | Week 2
    3 Topics
    |
    1 Quiz
  3. Projectile | Week 3
    5 Topics
  4. Equilibrium of Forces I | Week 4
    4 Topics
  5. Equilibrium of Forces II | Week 5
    4 Topics
  6. Stability of a Body | Week 6
    4 Topics
    |
    1 Quiz
  7. Simple Harmonic Motion (SHM) | Week 7
    4 Topics
  8. Speed, Velocity & Acceleration & Energy of Simple Harmonic Motion | Week 8
    5 Topics
    |
    1 Quiz
  9. Linear Momentum | Week 9
    6 Topics
    |
    1 Quiz
  10. Mechanical Energy & Machines | Week 10
    2 Topics
    |
    1 Quiz



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The maximum height (H) of a projectile is the highest vertical distance attained by a projectile as measured from the horizontal plane of projection.

To find the maximum height, H.

Using the equation under gravity,

v2 = U2 – 2gH

But u = u sin θ , V = 0 at maximum height

then 0 = (U sinθ)2 – 2gH

2gH = U2Sin2 θ

H = \( \frac {U^2 sin^2θ}{2g} \)

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