Lesson 3, Topic 3
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# Maximum Height

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The maximum height (H) of a projectile is the highest vertical distance attained by a projectile as measured from the horizontal plane of projection.

To find the maximum height, H.

Using the equation under gravity,

v2 = U2 – 2gH

But u = u sin θ , V = 0 at maximum height

then 0 = (U sinθ)2 – 2gH

2gH = U2Sin2 θ

H = $$\frac {U^2 sin^2θ}{2g}$$

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