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SS2: PHYSICS - 1ST TERM

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  1. Scalars & Vectors | Week 1
    5 Topics
    |
    1 Quiz
  2. Equations of Motion | Week 2
    3 Topics
    |
    1 Quiz
  3. Projectile | Week 3
    5 Topics
  4. Equilibrium of Forces I | Week 4
    4 Topics
  5. Equilibrium of Forces II | Week 5
    4 Topics
  6. Stability of a Body | Week 6
    4 Topics
    |
    1 Quiz
  7. Simple Harmonic Motion (SHM) | Week 7
    4 Topics
  8. Speed, Velocity & Acceleration & Energy of Simple Harmonic Motion | Week 8
    5 Topics
    |
    1 Quiz
  9. Linear Momentum | Week 9
    6 Topics
    |
    1 Quiz
  10. Mechanical Energy & Machines | Week 10
    2 Topics
    |
    1 Quiz



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Lesson 3, Topic 5
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Worked Examples – Projectile

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Example:

An missile is fired at a speed of 200ms-1 at an angle of 45°.

Find; 
(i) The height attained by the missile. 
(ii) How long it stays in the air?
(iii) The horizontal range.

Solution:

θ = 45°, U = 200ms-1, g = 10ms-2

(i) Height attained = \( \frac {U^2 Sin^2θ}{2g} \)

H = \( \frac {200^2 \: \times \: (0.7071)^2 }{20} \)

H = \( \frac {200^2 \: \times \: 0.5 }{20} = \frac {2000}{20} \)

 H = 1000m.

(ii) Time of Flight, T = \( \frac {2U Sinθ}{g} \)

  = \( \frac {2\: \times\: 200\: \times \:sin45^{\circ}}{10} \)

  = \( \frac {400 \: \times \: 0.6494 }{10} = \frac {259.779}{10} \)

  = 25.97Secs

(iii) Range =\( \frac {U^2 Sin2θ}{g} \)

= \( \frac {200^2 \: \times \: Sin2 \: \times \: 45}{10} \)

= \( \frac {200^2 \: \times \: Sin90}{10} \)

= \( \frac {40000 \: \times \: 1}{10} \)

= 4000m

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