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SS3: MATHEMATICS - 2ND TERM

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  1. Matrices I | Week 1
    6 Topics
  2. Matrices II | Week 2
    1 Topic
    |
    1 Quiz
  3. Commercial Arithmetic | Week 3
    7 Topics
    |
    1 Quiz
  4. Coordinate Geometry | Week 4
    8 Topics
    |
    1 Quiz
  5. Differentiation of Algebraic Expressions | Week 5 & 6
    7 Topics
  6. Application of Differentiation | Week 7
    4 Topics
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    1 Quiz
  7. Integration | Week 8
    8 Topics
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    1 Quiz



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 The gradient or slope of a line is defined as the ratio \( \frac{y-step}{x-step} \)   in going from one point to another on the line.

Gradient or slope of a line

 Gradient of AB = \( \frac{increase \; in \; y \; from \; A \; to \; B}{increase \; in \; x \; from \; A \; to \; B} \\ = \frac{CB}{AC} \)

Angle of slope

tan θ = \(\frac{opp}{adj} \\ = \frac{AC}{AB} \)

∴ The gradient of a line = tan (angle the line makes with the +ve x-axis)

Gradient of a line joining two points

The gradient of line joining A(x1, y1) and B(x2, y2)

= \( \frac{y_2 \; – \; y_1}{x_2 \; – \; x_1} \)

or \( \frac{y_1 \; – \; y_2}{x_1 \; – \; x_2} \)

Note that the coordinates must be subtracted in the same order.

Example:

Find the gradient of the line joining (3, -2) and (-5, -8) and the angle it makes with the positive x-axis.

Solution

Equation for Gradient of a line

= \( \frac{y_2 \; – \; y_1}{x_2 \; – \; x_1} \\ = \frac{-8 \; – \; (-2)}{-5 \; – \; (3)} \\ = \frac{-6}{-8} \\ = \frac{3}{4} \)

Angle = tanθ = \(\frac{opp}{adj}\\ = \frac{3}{4} \\ = \scriptsize 0.75 \)

θ = tan-1(0.75) = 36.87°

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