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Example:
Draw the graph of the line represented by the equation
4x + 2y = 5
Solution
Make a table of values
x | 0 | 1 | 2 |
y | \( \scriptsize2 \normalsize \frac {1}{2}\) | \( \frac {1}{2}\) | \( \scriptsize – 1 \normalsize \frac {1}{2}\) |
Substitute the values of x into the equation 4x + 2y = 5
When x = 0,
4(0) + 2y = 5
∴ y = \(\scriptsize 2 \frac {1}{2} \)
X = 1,
4(1)+2y = 5
2y = 5 – 4
2y = 1
∴ y = \( \frac {1}{2} \)
x = 2,
4(2) +2y = 5
8 +2y = 5
2y = 5 – 8
2y = 5 – 8
2y = -3
∴ y = \( \frac {-3}{2} \\ \; = \scriptsize – 1 \frac {1}{2} \)
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