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Lesson 10, Topic 4
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# Questions & Solutions

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Example

Calculate the frequency of the photons whose energy is required to eject surface electron with a k.e of 3.8 x 10-17eV and the work function of the metal is 2.66 x 10-17eV.

E = hf – hf0

Hf = E + hf0

f = $$\frac{E + hf_0}{H}$$

f = $$\frac{3.80 \times 10^{-17} + 2.66 \times 10 {-17}}{6.6 \times 10 {-34}}$$

f = $$\frac{6.46 \times 10^{-17} + 1.6 \times 10 {-19}}{6.6 \times 10 {-34}}$$

= 2.42 x 1014Hz

error: