Kofa Study Discussion
Feel Free to Ask any Questions on any Subject or the Kofa Study Platform.
We or the Community will... View more
Organizer:
- Organized by
-
-
i need help on how to solve this problem
-
i need help on how to solve this problem
simultaneous equations someone please help me – Andre has more money than Bob. If Andre gave Bob $20, they would have the same amount. While if Bob gave Andre $22, Andre would then have twice as much as Bob. How much does each one actually have?
-
5 Replies
-
X+y=20….(1)
2x+y=22…(2)
Using elimination method, subtract eqn(1) from (2).
2x-x +y-y=22-20
X=2.
Solving for y in eqn(1); substitute the value of X=2
2+y=20
Y=20-2
Y=18
-
hey that cant be right
because according to your definition they both have less than 20 dolllars
-
a – 20 = b + 20… 1
2(b – 22) = a + 22… 2
We can juggle those around for
a = b +40 and
2b – 44 = a + 22 so 2b – 66 = a
The equations are now:
a = b + 40 and
a = 2b – 66
ELIMINATION METHOD:
b + 40 = 2b – 66 so 40 = b – 66 making b = 106.
Plug b = 106 into new equations 1 and 2 for:
a = 106 + 40 (new equation 1) and
a = 212 – 66 (new equation 2)
This gives a = 146 and b = 106
-
For the purpose of the equations, I’ll call Andre and Bob a and b respectively.
a – 20 = b + 20 (equation 1)
2(b – 22) = a + 22 (equation 2)
We can juggle those around for
a = b +40 (equation 1r (re-arranged)) and
2b – 44 = a + 22 so 2b – 66 = a (equation 2r (rearranged))
The equations are now:
a = b + 40 (new equation 1) and
a = 2b – 66 (new equation 2)
Substitute from new equation 1 to new equation 2:
b + 40 = 2b – 66 so 40 = b – 66 making b = 106.
Plug b = 106 into new equations 1 and 2 for:
a = 106 + 40 (new equation 1) and
a = 212 – 66 (new equation 2)
This gives a = 146 and b = 106
-
Please, how can I unlock the lessons here? Thanks
Log in to reply.