JSS3 – Simple Equations Involving Fractions: 1st term Evaluation questions | Week 9

Solve the equation \( \frac{ x + 7}{2} + \frac{x + 21}{5} \scriptsize = 0 \)

If \( \frac{ 2y \; – \; 3}{4} + \frac{y \; – \;  1}{8} \scriptsize = 1 \)

find y

What value of x will make \( \frac{ x \: – \: 2}{7} \: – \:  \frac{5x \: – \:  3}{3} \scriptsize  \: – \: 5 = 0 \)

If  \( \frac{ a \: – \: 3}{4} \: – \:  \frac{5 \: + \: a}{2} \scriptsize = 0 \)

Find a

Find the value of b if  \(  \frac{7 + b}{5} \scriptsize = \; – \; 3 \)

If \( \scriptsize p =\normalsize \frac{35 \: – \: 3p}{2} \) 

Then p = ?

If \(  \frac{14}{1 \: + \: y} \scriptsize = 2 \)

Find y

What value of x makes\( \frac{5}{x \: – \: 3 } = \frac{4}{x} \) true

If \( \frac{2}{a + 3} = \frac{3}{3a – 1} \)

What is the value of a

Solve the equation \(  \frac{1}{y \: – \:1} \; – \; \frac{3}{2y\:  +\:  1} \scriptsize = 0 \)

Find the value of x in \(  \frac{12}{x} \:  – \: \frac{10}{x\: + \:1} \scriptsize = 0 \)

Solve \( \frac{3}{x\: + \:2} = \frac{2}{ x \: – \: 3} \)