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JSS1: MATHEMATICS - 2ND TERM

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  1. Algebraic Processes | Week 1
    4 Topics
    |
    1 Quiz
  2. Simplification of Algebraic Expressions | Week 2
    4 Topics
    |
    1 Quiz
  3. Simplification of Algebraic Expressions 2 (Use of Brackets) | Week 3
    4 Topics
    |
    1 Quiz
  4. Simple Equations | Week 4
    1 Topic
    |
    1 Quiz
  5. Simple Equations II | Week 5
    3 Topics
    |
    1 Quiz
  6. Plane Shapes I | Week 6
    5 Topics
    |
    2 Quizzes
  7. Plane Shapes II | Week 7
    7 Topics
    |
    1 Quiz
  8. Plane Shapes III | Week 8
    7 Topics
    |
    1 Quiz
  9. Decimal and Percentages I | Week 9
    2 Topics
    |
    1 Quiz
  10. Decimal and Percentages | Week 10
    3 Topics
    |
    1 Quiz



Lesson Progress
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Perimeter   =   2L  +   2b
or 2( L   +   b)  
or  2 (L  +  W)

Where  L  =  Length
b/W =  Breadth / Width

perimeter of a rectangle

Example 1: 

The length of a rectangular room is 8m, and the width (breadth) is 6m. Find the perimeter of the room.

Solution:

Length of the room, L = 8m

Width of the room, W = 6m

Perimeter  =  2 (L  +   W)

Perimeter =  2(8  +  6)

= 2  ×  14

= 28m 

Example 2:

A rectangle is 5m long and 2000mm wide. Find the perimeter.

Solution:

First, convert to the same unit, so we will convert millimetre to metre. Remember there are 1000 millimetres in 1 metre. 

Width (w)   =   2000mm

= 2000 ÷ 1000

= \( \frac{2000}{1000} \)

Width = 2m

Length (l) = 5m

CONSTRUCTION120

Perimeter  = 2 (L  + W)

= 2 × (5  +  2)

= 2  ×  7

Perimeter = 14m

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