Back to Course
JSS1: MATHEMATICS - 1ST TERM
0% Complete
0/0 Steps
-
Whole Numbers I | Week 13 Topics|1 Quiz
-
Whole Numbers II | Week 21 Topic|1 Quiz
-
Counting in Base Two | Week 34 Topics|1 Quiz
-
Arithmetic Operations | Week 43 Topics|1 Quiz
-
Lowest Common Multiple (LCM) | Week 52 Topics|1 Quiz
-
Highest Common Factor | Week 61 Topic|1 Quiz
-
Fraction | Week 77 Topics|1 Quiz
-
Basic Operations with Fractions I | Week 83 Topics|1 Quiz
-
Basic Operations with Fractions II | Week 91 Topic|1 Quiz
-
Directed Numbers | Week 103 Topics|1 Quiz
-
Estimation and Approximation I | Week 113 Topics|1 Quiz
-
Estimation and Approximation II | Week 126 Topics|1 Quiz
Lesson 7,
Topic 2
In Progress
How To Find Equivalent Fractions
Lesson Progress
0% Complete
Topic Content:
- How To Find Equivalent Fractions
To find an equivalent fraction with a larger numerator and denominator, simply multiply both the numerator and the denominator of the given fraction by the same number.
For example:
\( \frac {2}{3} = \frac {2}{3}\: \times \: \frac {3}{3}= \frac {6}{9} \)That is, \( \frac {2}{3}\)is equivalent to \( \frac {6}{9}\)
Worked Example 7.2.1:
Convert \(\frac{2}{9}\) into an equivalent fraction with the denominator 27.
Solution

Divide the second denominator by the first denominator to obtain the multiplier.
i.e. 27 ÷ 9 = 3
\( \frac {2}{9}= \frac {2 \: \times \: 3}{9 \: \times \: 3} = \frac {6}{27} \)⇒ \( \frac {2}{9}= \frac {6}{27} \)
Worked Example 7.2.2:
Find the missing part of these fractions:

Solution
You can use \( \frac {20}{50}\) as your reference fraction because both its numerator and denominator are given.
That is, \( \frac {20}{50} = \frac {2}{5} \) (i.e. divide by 10)
We can use the fraction to obtain the multipliers.
\( \frac {?}{10} = \frac {2 \: \times \: 2}{2 \: \times \: 5} = \frac {4}{10} \) \( \frac {12}{?} = \frac {6 \: \times \: 2}{6 \: \times \: 5} = \frac {12}{30} \) \( \frac {?}{80} = \frac {16 \: \times \: 2}{16 \: \times \: 5} = \frac {32}{80} \)