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JSS1: MATHEMATICS  1ST TERM
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Whole Numbers I  Week 13 Topics1 Quiz

Whole Numbers II  Week 21 Topic1 Quiz

Counting in Base Two  Week 34 Topics1 Quiz

Arithmetic Operations  Week 43 Topics1 Quiz

Lowest Common Multiple (LCM)  Week 52 Topics1 Quiz

Highest Common Factor  Week 61 Topic1 Quiz

Fraction  Week 77 Topics1 Quiz

Basic Operations with Fractions I  Week 83 Topics1 Quiz

Basic Operations with Fractions II  Week 91 Topic1 Quiz

Directed Numbers  Week 103 Topics1 Quiz

Estimation and Approximation I  Week 113 Topics1 Quiz

Estimation and Approximation II  Week 126 Topics1 Quiz
Lesson 7,
Topic 2
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How To Find Equivalent Fractions
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Topic Content:
 How To Find Equivalent Fractions
To find an equivalent fraction with a larger numerator and denominator, simply multiply both the numerator and the denominator of the given fraction by the same number.
For example:
\( \frac {2}{3} = \frac {2}{3}\: \times \: \frac {3}{3}= \frac {6}{9} \)That is, \( \frac {2}{3}\)is equivalent to \( \frac {6}{9}\)
Worked Example 7.2.1:
Convert \(\frac{2}{9}\) into an equivalent fraction with the denominator 27.
Solution
Divide the second denominator by the first denominator to obtain the multiplier.
i.e. 27 ÷ 9 = 3
\( \frac {2}{9}= \frac {2 \: \times \: 3}{9 \: \times \: 3} = \frac {6}{27} \)⇒ \( \frac {2}{9}= \frac {6}{27} \)
Worked Example 7.2.2:
Find the missing part of these fractions:
Solution
You can use \( \frac {20}{50}\) as your reference fraction because both its numerator and denominator are given.
That is, \( \frac {20}{50} = \frac {2}{5} \) (i.e. divide by 10)
We can use the fraction to obtain the multipliers.
\( \frac {?}{10} = \frac {2 \: \times \: 2}{2 \: \times \: 5} = \frac {4}{10} \) \( \frac {12}{?} = \frac {6 \: \times \: 2}{6 \: \times \: 5} = \frac {12}{30} \) \( \frac {?}{80} = \frac {16 \: \times \: 2}{16 \: \times \: 5} = \frac {32}{80} \)