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SS1: CHEMISTRY - 1ST TERM

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  1. Introduction to Chemistry and Laboratory Apparatus | Week 1
    5 Topics
    |
    1 Quiz
  2. Nature of Matter | Week 2
    3 Topics
    |
    1 Quiz
  3. Separation Techniques I | Week 3
    1 Topic
  4. Separation Techniques II | Week 4
    5 Topics
    |
    1 Quiz
  5. Particulate Nature of Matter I | Week 5
    5 Topics
    |
    1 Quiz
  6. Particulate Nature of Matter II | Week 6
    9 Topics
    |
    1 Quiz
  7. Symbols, Formulae & Oxidation Number | Week 7
    7 Topics
    |
    1 Quiz
  8. Laws of Chemical Combination | Week 8
    4 Topics
    |
    1 Quiz
  9. Chemical Equation & Chemical Combination (Chemical Bonding) I | Week 9
    4 Topics
    |
    1 Quiz
  10. Chemical Combination (Chemical Bonding) II | Week 10
    4 Topics
    |
    1 Quiz
  11. Chemical Combination (Chemical Bonding) III & Shapes of Covalent Molecules | Week 11
    3 Topics
    |
    1 Quiz

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Topic Content:

  • Hydrated Salts

Hydrated Salts are salts containing water of crystallization. The number of water molecules is indicated by mono, di, tri, tetra, penta etc. according to the number of water of crystallization.

In naming the corresponding anhydrous salt i.e. without molecules of water, the salt is first named, followed by a full stop, and then the number of water molecules of water is written down.

Example:

 

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Theory Question 1

1. Write down the formulae of the following: 

(i) Ozone   

Answer: O3  

 

(ii) Hydrogen sulphate   

Answer: Hydrogen Sulphate
H+1 SO4-1
⇒ HSO4–

 

(iii) Magnesium tetraoxosulphate (VI)  

Answer:

Mg2+  SO42-

MgSO4 .7H2O

 

(iv) Oxygen molecule

Answer:  O2

 

(v) Bromine molecule 

Answer:  Br2

Theory Question 2

Calculate the Oxidation number of the underlined elements

(a) H2SO4  

Solution:

(1 × 2) + S + (-2 × 4) = 0

2 + S – 8 = 0

S – 6 = 0

S = +6

The oxidation number of Sulphur (S) in H2SO4  = +6

        
(b) CO2   

Solution:

C + (2 × -2) = 0

C – 4 = 0

C = +4

The oxidation number of carbon (C) in CO2  = +4

    
(c) NaH      

Solution:

Na + (-1) = 0

Na – 1 = 0

Na = +1

Note – H is an hydride; hence oxidation number is -1.

The oxidation number of sodium (Na) in NaH is +1.

  
(d) Cr2O   

Solution:

2Cr + (-2) = 0

2Cr – 2 = 0

2Cr = 2

Cr = \( \frac{2}{2} \)

Cr = +1.

The oxidation number of chromium (Cr) in Cr2O  is +1

        
(e) FeCl2  

Cl– = -1

Fe + (2 × -1) = 0

Fe – 2 = 0

Fe = +2

The oxidation number of Iron (Fe) in FeCl2 is +2

     
(f) NaMnO4

Solution:

+1 + Mn + (-2 × 4) = 0

1 + Mn – 8 = 0

Mn – 7 = 0

Mn = +7

The oxidation number of Manganese (Mn) in NaMnO4 is +7

Theory Question 3

3. Give the IUPAC name of the following compounds

Answer:

(a) MgO – Magnesium oxide       
(b) Na2SO4 –  Sodium Sulphate
(c) FeO3 – Iron (III) oxide         
(d) Al2O3 – Aluminium oxide

Theory Question 4

(a) Give the symbols of the following elements:

(i) Silicon – ‘S’       
(ii) Chlorine – ‘Cl’
(iii) Silver  – ‘Ag’        
(iv) Potassium – K’

(b) Name the elements with the following symbols:

(i) Sn  – Tin       
(ii) Br – Bromine
(iii) Cr  – Chromium         
(iv) Be – Beryllium

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